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| 1 | +//189. Rotate Array |
| 2 | + |
| 3 | +//Given an array, rotate the array to the right by k steps, |
| 4 | +//where k is non-negative. |
| 5 | + |
| 6 | +//Example 1: |
| 7 | +// |
| 8 | +//Input: nums = [1,2,3,4,5,6,7], k = 3 |
| 9 | +//Output: [5,6,7,1,2,3,4] |
| 10 | + |
| 11 | +//Explanation: |
| 12 | +//rotate 1 steps to the right: [7,1,2,3,4,5,6] |
| 13 | +//rotate 2 steps to the right: [6,7,1,2,3,4,5] |
| 14 | +//rotate 3 steps to the right: [5,6,7,1,2,3,4] |
| 15 | + |
| 16 | +//Example 2: |
| 17 | +// |
| 18 | +//Input: nums = [-1,-100,3,99], k = 2 |
| 19 | +//Output: [3,99,-1,-100] |
| 20 | + |
| 21 | +//Explanation: |
| 22 | +//rotate 1 steps to the right: [99,-1,-100,3] |
| 23 | +//rotate 2 steps to the right: [3,99,-1,-100] |
| 24 | + |
| 25 | +//Constraints: |
| 26 | + |
| 27 | +//1 <= nums.length <= 105 |
| 28 | +//-231 <= nums[i] <= 231 - 1 |
| 29 | +//0 <= k <= 105 |
| 30 | + |
| 31 | +public class Rotate_Array { |
| 32 | + |
| 33 | + public static void main(String[] args) { |
| 34 | +// take array |
| 35 | + int[] nums = { 1, 0, 0, 0, 0, 0, 0 }; |
| 36 | +// take value for rotation |
| 37 | + int k = 2; |
| 38 | +// call the function rotate |
| 39 | + rotate(nums, k); |
| 40 | + } |
| 41 | + |
| 42 | +// ----------------------------------------------- |
| 43 | +// method one o(n2) time complexity |
| 44 | + |
| 45 | +// take two for loops and with the help of temp variable rotate array |
| 46 | + |
| 47 | +// ----------------------------------------------- |
| 48 | +// public static void rotate(int[] nums, int k) { |
| 49 | +// int temp,n=nums.length,i,j; |
| 50 | +// for (i = 0; i < k; i++) { |
| 51 | +// temp = nums[n - 1]; |
| 52 | +// for (j = n - 1; j > 0; j--) { |
| 53 | +// nums[j] = nums[j - 1]; |
| 54 | +// } |
| 55 | +// nums[0] = temp; |
| 56 | +// } |
| 57 | +// |
| 58 | +// for(j=0;j<n;j++) { |
| 59 | +// System.out.print(nums[j]+ " "); |
| 60 | +// } |
| 61 | +// } |
| 62 | + |
| 63 | +// ----------------------------------------------- |
| 64 | +// method for get perfect solution in leetcode |
| 65 | + |
| 66 | +// take the another array for storing the value into that but |
| 67 | +// that is not proper answer for the leetcode |
| 68 | +// ----------------------------------------------- |
| 69 | + |
| 70 | +// private static void rotate(int[] nums, int k) { |
| 71 | +// int[] reordered = new int[nums.length]; |
| 72 | +// for (int i = 0; i < nums.length; i++) |
| 73 | +// reordered[i] = nums[(k + i + 1) % nums.length]; |
| 74 | +// System.out.print("["); |
| 75 | +// for (int j = 0; j < nums.length; j++) { |
| 76 | +// |
| 77 | +// if(j!=(nums.length-1)) |
| 78 | +// System.out.print(reordered[j] + ","); |
| 79 | +// else |
| 80 | +// System.out.print(reordered[j]); |
| 81 | +// } |
| 82 | +// System.out.println("]"); |
| 83 | +// } |
| 84 | + |
| 85 | +// ----------------------------------------------- |
| 86 | +// code submitted in leetcode |
| 87 | + |
| 88 | +// first copy the array in duplicate array. |
| 89 | +// than using the k value and positioning with the i set nums array |
| 90 | +// ----------------------------------------------- |
| 91 | + private static void rotate(int[] nums, int k) { |
| 92 | + int[] duplicate = new int[nums.length]; |
| 93 | + for (int i = 0; i < nums.length; i++) |
| 94 | + duplicate[i] = nums[i]; |
| 95 | + |
| 96 | + for (int i = 0; i < nums.length; i++) |
| 97 | + nums[(k + i) % nums.length] = duplicate[i]; |
| 98 | + |
| 99 | + for (int j = 0; j < nums.length; j++) { |
| 100 | + System.out.print(nums[j] + " "); |
| 101 | + } |
| 102 | + |
| 103 | + } |
| 104 | + |
| 105 | +} |
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